CheckPoint 156-835 CCME Exam Practice Test Instant Access

Question 1

What cannot be learned from the output of asg perf -v -p command?

AAverage CPU usage on Appliances

BReal-time throughput

CAverage CPU usage on Orchestrators

DPer-path distribution

Answer : C

Question 2

What command should be used for collecting diagnostic information about the orchestrator?

Acpinfo

Borch_info

Ccpview

Dasg pert -v

Answer : B

Question 3

What is the basic installation sequence of the Orchestrator in case of single Orchestrator?

1. Create a Security Group

2. Configure Default Gateway

3. Connect with Serial Console cable to the Orchestrator

4. Configure IP for one of its Management interfaces

5. Connect an appliance to a downlink port

6. Change Orchestrator amount to 1

7. Browse to the Orchestrator's WebUI

A3-4-2-6-5-7-1

B3-1-7-2-4-6-5

C1-4-2-5-7-3-6

D7-4-2-5-3-1-6

Answer : A

Question 4

There are two 10Gbps dual-port NIC installed on a 6800 appliance. Which interfaces should be connected to Orchestrator 1 for downlinks' intra-orchestrator redundancy when using two Orchestrators?

APort 1 in Slot 1 and Port 2 in Slot 1

BPort 1 in Slot 2 and Port 2 in Slot 1

CAny pair of available ports

DPort 1 in Slot 1 and Port 1 in Slot 2

Answer : D

Question 5

What is a Security Group?

ALogical group of computer and network resources

BGroup of security administrators

CGroup of security gateways

DGroup of appliances with enabled NGTX software blades

Answer : C

Question 6

What cannot be learned from the output of lldpctl?

ADistribution mode

BOrchestrator's IP

CSerial number of Appliance

DAppliance model

Answer : A

Question 7

There are two appliances within the same Security Group. One of them is connected by One downlink only, another one by Two downlinks. Assuming there's no NAT and no VPN, what would be proportion of

traffic distribution done by Orchestrator?

A66%/33%

B100%/0%

C50%/50%

D33%/66%

Answer : C

CheckPoint 156-835 Check Point Certified Maestro Expert CCME Exam Practice Test