NABP North American Pharmacist Licensure Examination Exam Practice Test

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Total 155 questions
Question 1

What is the active ingredient found in the medicine Adalat?



Answer : A

The dihydropyridine drug -- nifedipine -- is the active ingredient found in the medicine Adalat. Nifedipine is used to treat angina, Reynaud's phenomenon and hypertension. It is also used as a tocolytic agent in premature labor.


Question 2

Pyridoxine is often used in pregnancy to manage which of the following conditions?



Answer : C

Pyridoxine is combined with doxylamine to treat morning sickness in pregnant women.


Question 3

Which of these cardiovascular drug classes is most associated with tachyphylaxis?



Answer : E

Tachyphylaxis is the phenomenon where a patient experiences a rapid form of drug tolerance. Nitrates exhibit this property. It means that the patient becomes tolerance very quickly and so repeat doses become more and more ineffective. To overcome the problem of tachyphyaxis, then, sufficient time must elapse between doses.


Question 4

Aluminum levels may rise to toxic levels in patients with renal failure if administered with which of these medicines?



Answer : A

Sucralfate is a drug used to treat active duodenal ulcers and may also be used to treat GERD or stress ulcers.


Question 5

What is the standard loading dose for clopidogrel in the treatment of ACS?



Answer : E

300mg is the standard loading dose of clopidogrel -- an antiplatelet drug -- in the treatment of acute coronary syndrome (ACS).


Question 6

Which of the following would be most appropriate to treat stenotrophomonas maltophilia?



Answer : D

Primary treatment for stenotrophomonas maltophilia is SMX-TMP. Meropenem, ciprofloxacin, and vancomycin have no coverage.


Question 7

Calculate the Osmolarity of 3% hypertonic saline?



Answer : A

Osmolarity = mOsmol/L = (wt of substance (g/mL))/(MW(g/mol)) (# of particles) 1000 Weight of substance: 3% = (3g/100mL) = (xg/1000mL), x = 30g/L. # of particles NaCL: Na+ + Cl- (2 particles). mOsmol/L = (30g/L)/ (58.5g/mol) 2 1000 = 1,025.6. The answer is 1026 mOsmol/L.


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Total 155 questions